Termination w.r.t. Q of the following Term Rewriting System could not be shown:

Q restricted rewrite system:
The TRS R consists of the following rules:

s11(s11(s01(s01(x)))) -> s01(s01(s01(s11(s11(s11(x))))))

Q is empty.


QTRS
  ↳ Non-Overlap Check

Q restricted rewrite system:
The TRS R consists of the following rules:

s11(s11(s01(s01(x)))) -> s01(s01(s01(s11(s11(s11(x))))))

Q is empty.

The TRS is non-overlapping. Hence, we can switch to innermost.

↳ QTRS
  ↳ Non-Overlap Check
QTRS
      ↳ DependencyPairsProof

Q restricted rewrite system:
The TRS R consists of the following rules:

s11(s11(s01(s01(x)))) -> s01(s01(s01(s11(s11(s11(x))))))

The set Q consists of the following terms:

s11(s11(s01(s01(x0))))


Using Dependency Pairs [1,13] we result in the following initial DP problem:
Q DP problem:
The TRS P consists of the following rules:

S11(s11(s01(s01(x)))) -> S11(x)
S11(s11(s01(s01(x)))) -> S11(s11(x))
S11(s11(s01(s01(x)))) -> S11(s11(s11(x)))

The TRS R consists of the following rules:

s11(s11(s01(s01(x)))) -> s01(s01(s01(s11(s11(s11(x))))))

The set Q consists of the following terms:

s11(s11(s01(s01(x0))))

We have to consider all minimal (P,Q,R)-chains.

↳ QTRS
  ↳ Non-Overlap Check
    ↳ QTRS
      ↳ DependencyPairsProof
QDP

Q DP problem:
The TRS P consists of the following rules:

S11(s11(s01(s01(x)))) -> S11(x)
S11(s11(s01(s01(x)))) -> S11(s11(x))
S11(s11(s01(s01(x)))) -> S11(s11(s11(x)))

The TRS R consists of the following rules:

s11(s11(s01(s01(x)))) -> s01(s01(s01(s11(s11(s11(x))))))

The set Q consists of the following terms:

s11(s11(s01(s01(x0))))

We have to consider all minimal (P,Q,R)-chains.